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A-Level Physical quantities, units, measurement uncertainty and vector basics

What the A-Level syllabus expects for Physical quantities, units, measurement uncertainty and vector basics, and how to practise it.

What the syllabus expects

How it's examined

Questions on this topic most often ask you to find, state. About 4% of the past-paper style questions in Rae's bank for this subject sit in this topic.

Worked examples

Example 1 (2 marks)

(ii) Write the units of the permittivity of free space in terms of SI base units. units = ..............

Show the worked answer

From Coulomb's law F = Q²/(4πε₀r²), so ε₀ = Q²/(F·r²). Units: [Q²] = (A s)² = A² s²; [F·r²] = N·m² = (kg m s⁻²)·m² = kg m³ s⁻². Therefore ε₀ has units (A² s²)/(kg m³ s⁻²) = kg⁻¹ m⁻³ s⁴ A².

Example 2 (2 marks)

(b) The circular capacitor plates are found to have a diameter of 6.50 cm and to be separated by 5.42 mm. State which instrument is used for each measurement and give a reason. instrument for measuring the diameter .............. instrument for measuring the separation .............. reason ..............

Show the worked answer

Diameter (6.50 cm): use vernier calipers. Separation (5.42 mm): use a micrometer screw gauge. Reason: the micrometer reads to 0.01 mm, the fine resolution needed for the small plate separation, but its jaws/anvil gap (about 25 mm max) is too small to span the 6.50 cm diameter, so the larger diameter is measured with vernier calipers, which still give the 0.01 cm precision the quoted value requires.

Example 3 (4 marks)

A wire hangs vertically from a fixed point with a load on its lower end. Measurements give diameter d = 0.40 ± 0.02 mm and load F = 25.0 ± 0.5 N. The stress is σ = 4F/(πd²). Find σ and its uncertainty. [4]

Show the worked answer

Convert the diameter to metres: d = 0.40 mm = 0.40 × 10⁻³ m, so d² = (0.40 × 10⁻³)² = 1.6 × 10⁻⁷ m². Substitute into σ = 4F/(πd²): σ = (4 × 25.0)/(π × 1.6 × 10⁻⁷) = 100/(5.0265 × 10⁻⁷) = 1.98944 × 10⁸ ≈ 1.98 × 10⁸ N m⁻². For a quotient with a squared quantity, fractional uncertainties add, with the power as multiplier: Δσ/σ = ΔF/F + 2Δd/d. ΔF/F = 0.5/25.0 = 0.02 and 2Δd/d = 2 × 0.02/0.40 = 0.10, so Δσ/σ = 0.02 + 0.10 = 0.12. Δσ = 0.12 × 1.989 × 10⁸ = 0.239 × 10⁸ ≈ 0.2 × 10⁸ N m⁻² (uncertainty quoted to 1 s.f.). Quote σ to the same precision as its uncertainty: σ = (2.0 ± 0.2) × 10⁸ N m⁻².

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