Rae

HomeSubjectsA-Level H2 Chemistry › Trends in the elements across a period and down a group

A-Level Trends in the elements across a period and down a group

What the A-Level syllabus expects for Trends in the elements across a period and down a group, and how to practise it.

What the syllabus expects

How it's examined

Questions on this topic most often ask you to explain, describe, outline, state. About 6% of the past-paper style questions in Rae's bank for this subject sit in this topic.

Worked examples

Example 1 (3 marks)

Describe and account for the way thermal stability changes across the hydrogen halides HCl, HBr and HI, including an equation for the decomposition reaction.

Show the worked answer

Thermal stability decreases from HCl to HBr to HI (HCl > HBr > HI). Going down the group the halogen atom gets larger, so the H-X bond length increases and bond overlap becomes poorer; the H-X bond enthalpy falls (H-Cl ~431 > H-Br ~366 > H-I ~299 kJ/mol). A weaker bond is broken more easily on heating, so HI is the least thermally stable and decomposes most readily. Decomposition equation (e.g. for HI): 2HI(g) -> H2(g) + I2(g).

Example 2 (3 marks)

With reference to section 24 of the data booklet, account for why acidified aqueous potassium iodide develops a brown colour after being left open to the air for some time.

Show the worked answer

The brown colour is due to iodine, I2, being produced. Oxygen from the air oxidises the iodide ions in acidic solution. Relevant standard electrode potentials: O2 + 4H+ + 4e- -> 2H2O, E = +1.23 V; I2 + 2e- -> 2I-, E = +0.54 V. Since E(O2/H2O) > E(I2/I-), Ecell = 1.23 - 0.54 = +0.69 V (positive), so O2 is able to oxidise I- to I2. Overall: O2 + 4H+ + 4I- -> 2I2 + 2H2O.

Example 3 (5 marks)

When a hot glass rod is thrust into a gas jar containing gaseous HI, a violet vapour appears. Carrying out the same experiment with HBr produces no visible change. Explain these observations.

Show the worked answer

The hot rod supplies enough energy to decompose the hydrogen halide: 2HX -> H2 + X2. The violet vapour with HI is iodine vapour (I2), showing that HI has been thermally decomposed to give I2. With HBr, no visible change (no brown/orange Br2 vapour formed appreciably) means HBr is not readily decomposed under the same conditions. The reason lies in bond strength / thermal stability, which follows the trend down Group 17. The H-X bond strength decreases from HCl to HBr to HI because the halogen atom gets larger, the bonding electrons are further from the nucleus, so the bond is longer and weaker. HI has the weakest H-X bond, so it is the least thermally stable and is readily decomposed by the hot rod, liberating violet I2 vapour. HBr has a stronger H-Br bond (more thermally stable), so it is not decomposed by the hot rod and no coloured vapour appears.

More worked questions on this topic

Ask about Trends in the elements across a period and down a groupUse Rae in Telegram

More A-Level H2 Chemistry topics

The make-up of the atom and how its electrons are arranged · How atoms bond and how that governs a substance's behaviour · Ideal gases and working with gas mixtures · Competing definitions of acids and bases · The mole and reacting-quantity calculations · Enthalpy, entropy and the feasibility of reactions · all of A-Level H2 Chemistry