Rae

HomeSubjectsA-Level H2 Chemistry › How atoms bond and how that governs a substance's behaviour

A-Level How atoms bond and how that governs a substance's behaviour

What the A-Level syllabus expects for How atoms bond and how that governs a substance's behaviour, and how to practise it.

What the syllabus expects

How it's examined

Questions on this topic most often ask you to explain, show, state, compare. About 6% of the past-paper style questions in Rae's bank for this subject sit in this topic.

Worked examples

Example 1 (3 marks)

The table below gives the melting points, in °C, of the chlorides and iodides of the two elements iron and silicon. Table 1.2 (chloride) iron: 674, silicon: -68 (iodide) iron: 590, silicon: 120 Using ideas about structure and bonding, account for the differences in melting point among FeCl2, SiCl4 and SiI4.

Show the worked answer

FeCl2 has a giant ionic lattice: strong electrostatic forces of attraction between Fe2+ and Cl- ions must be overcome, so its melting point is very high (674 C). SiCl4 and SiI4 are simple molecular (discrete covalent molecules); only weak instantaneous-dipole/induced-dipole (van der Waals/dispersion) forces act between the molecules, so their melting points are low. SiI4 (120 C) melts higher than SiCl4 (-68 C) because the iodine atoms have more electrons/larger electron clouds, giving a more polarisable molecule and therefore stronger dispersion forces than in SiCl4.

Example 2 (3 marks)

PCl5, a chloride of Period 3, is often used to chlorinate organic compounds and as a catalyst in their preparation. It is made industrially by reacting Cl2 with PCl3. Reaction (1): PCl3(g) + Cl2(g) ⇌ PCl5(g) Apply VSEPR theory to predict and account for the shape and bond angle of PCl3, and include a suitable diagram showing the shape of the PCl3 molecule.

Show the worked answer

P has 5 valence electrons; in PCl3 it forms 3 bonding pairs to Cl and retains 1 lone pair, giving 4 electron domains around P. Four domains adopt a tetrahedral arrangement, but with one position occupied by a lone pair the molecular shape is trigonal pyramidal. The lone pair-bond pair repulsion is greater than bond pair-bond pair repulsion, so the Cl-P-Cl angle is compressed below 109.5 deg to about 100 deg. Diagram: P at apex with a lone pair on top and three P-Cl bonds fanning down to the three Cl atoms.

Example 3 (2 marks)

Explain how a sigma (σ) bond and a pi (π) bond are each formed.

Show the worked answer

A sigma (sigma) bond is formed by the head-on (end-on) overlap of two orbitals along the line joining the two nuclei (the internuclear axis), giving a region of electron density concentrated directly between the nuclei. A pi (pi) bond is formed by the sideways (lateral) overlap of two parallel p orbitals, giving regions of electron density above and below the internuclear axis.

More worked questions on this topic

Ask about How atoms bond and how that governs a substance's behaviourUse Rae in Telegram

More A-Level H2 Chemistry topics

The make-up of the atom and how its electrons are arranged · Ideal gases and working with gas mixtures · Competing definitions of acids and bases · Trends in the elements across a period and down a group · The mole and reacting-quantity calculations · Enthalpy, entropy and the feasibility of reactions · all of A-Level H2 Chemistry