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O-Level Redox Chemistry

oxidation and reduction, and electrochemistry

What the syllabus expects

How it's examined

Questions on this topic most often ask you to explain, state, describe, suggest. About 6% of the past-paper style questions in Rae's bank for this subject sit in this topic.

Worked examples

Example 1 (3 marks)

B8 OR The head of a safety match holds potassium chlorate(V), KClO3, while the striking surface of the box contains red phosphorus, P4, together with an impurity. Striking the match on this surface triggers the reaction shown by the equation: 3P4 + 10KClO3 -> 3P4O10 + 10KCl Using changes in oxidation states, explain why this reaction is classed as a redox reaction.

Show the worked answer

Assign oxidation states. Phosphorus: 0 in P4 (element) rising to +5 in P4O10, so P is oxidised (oxidation state increases). Chlorine: +5 in KClO3 falling to -1 in KCl, so Cl is reduced (oxidation state decreases). Because oxidation and reduction occur together in the same reaction, it is a redox reaction.

Example 2 (2 marks)

Construct the half-equation for the conversion of ethanedioate ions, C2O4²⁻, into carbon dioxide, CO2.

Show the worked answer

Ethanedioate is oxidised to carbon dioxide, so electrons are released. Balance carbon: one C2O4²- gives 2 CO2. Oxygen is already balanced (4 on each side); no H or O species need adding. Balance charge: left side is 2-, right side (2CO2) is 0, so add 2 electrons to the right. C2O4²- -> 2CO2 + 2e^-

Example 3 (2 marks)

The zinc electrode was swapped for a silver one, after which the voltmeter read -0.52 V. Suggest why the voltmeter reading turned negative. [Total: 10]

Show the worked answer

In the original cell zinc was the more reactive electrode, so it was the negative terminal and set the direction of electron flow, giving a positive reading. Silver is less reactive than the other (fixed) electrode, so when it replaces zinc the roles of the two electrodes are reversed: the electrode that was positive is now the more reactive (negative) one. Electrons therefore flow through the meter in the opposite direction, so the voltmeter deflects the other way and reads a negative value.

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More O-Level Pure Chemistry topics

Experimental Chemistry · The Particulate Nature of Matter · Chemical Bonding and Structure · Chemical Calculations · Acid-Base Chemistry · Qualitative Analysis · all of O-Level Pure Chemistry