Probability: replacement, tree diagrams and checking outcomes
Probability starts with a clearly defined experiment. Decide whether outcomes are equally likely and whether a selection changes what is available for the next selection. The words ‘without replacement’ change the second denominator.
Choose the method
For equally likely outcomes, probability = favourable outcomes/total outcomes. The answer must lie between 0 and 1.
Multiply conditional probabilities along a tree branch. Add the probabilities of mutually exclusive branches that produce the event you want.
Use a complement for ‘at least one’ when it is easier: P(at least one) = 1 - P(none). Independence must be given or justified; separate events are not automatically independent.
Worked examples
Example 1
A bag contains 3 red and 2 blue counters. Two are drawn without replacement. Find P(both red).
The first draw is red with probability 3/5.
After a red draw, 2 red counters remain among 4 counters. The second probability is 2/4.
P(both red) = 3/5 × 2/4 = 3/10.
Example 2
For the same bag, find P(one red and one blue) without replacement.
Red then blue: 3/5 × 2/4 = 3/10.
Blue then red: 2/5 × 3/4 = 3/10.
These branches cannot happen together, so add: 3/10 + 3/10 = 3/5.
Try it yourself
A fair die is rolled twice independently. Find P(at least one six).
Show the worked answer
The complement is no six on either roll: (5/6)² = 25/36.
Required probability = 1 - 25/36 = 11/36.
Common mistakes
Count both orders when the event can occur in either order.
With replacement, the original probabilities return. Without replacement, update the counts after every draw.
Original Rae practice, prepared with AI assistance. Selected numerical results and their displayed working are automatically checked at publication; this does not verify every explanation. Curriculum references checked on 5 September 2026. No teacher review or SEAB endorsement is claimed.
What the syllabus expects
probability as a way of measuring chance
the probability of single events Scope: includes listing every possible outcome in a simple chance setting to compute the probability
the probability of simple combined events Scope: includes using possibility diagrams and tree diagrams where suitable
adding and multiplying probabilities for mutually exclusive events and for independent events